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Question
12x^{2}-18x
Factor the expression
6x\left(2x-3\right)
Evaluate
12x^{2}-18x
Rewrite the expression
6x\times 2x-6x\times 3
Solution
6x\left(2x-3\right)
Show Solutions
Find the roots
x_{1}=0,x_{2}=\frac{3}{2}
Alternative Form
x_{1}=0,x_{2}=1.5
Evaluate
12x^{2}-18x
To find the roots of the expression,set the expression equal to 0
12x^{2}-18x=0
Factor the expression
More Steps
Evaluate
12x^{2}-18x
Rewrite the expression
6x\times 2x-6x\times 3
\text{Factor out }6x\text{ from the expression}
6x\left(2x-3\right)
6x\left(2x-3\right)=0
When the product of factors equals 0,at least one factor is 0
\begin{align}&6x=0\\&2x-3=0\end{align}
\text{Solve the equation for }x
\begin{align}&x=0\\&2x-3=0\end{align}
\text{Solve the equation for }x
More Steps
Evaluate
2x-3=0
Move the constant to the right-hand side and change its sign
2x=0+3
Removing 0 doesn't change the value,so remove it from the expression
2x=3
Divide both sides
\frac{2x}{2}=\frac{3}{2}
Divide the numbers
x=\frac{3}{2}
\begin{align}&x=0\\&x=\frac{3}{2}\end{align}
Solution
x_{1}=0,x_{2}=\frac{3}{2}
Alternative Form
x_{1}=0,x_{2}=1.5
Show Solutions
