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Question

1-t^{2}\times 26
Simplify the expression
1-26t^{2}
Evaluate
1-t^{2}\times 26
Solution
1-26t^{2}
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Find the roots
t_{1}=-\frac{\sqrt{26}}{26},t_{2}=\frac{\sqrt{26}}{26}
Alternative Form
t_{1}\approx -0.196116,t_{2}\approx 0.196116
Evaluate
1-t^{2}\times 26
To find the roots of the expression,set the expression equal to 0
1-t^{2}\times 26=0
Use the commutative property to reorder the terms
1-26t^{2}=0
Move the constant to the right-hand side and change its sign
-26t^{2}=0-1
Removing 0 doesn't change the value,so remove it from the expression
-26t^{2}=-1
Change the signs on both sides of the equation
26t^{2}=1
Divide both sides
\frac{26t^{2}}{26}=\frac{1}{26}
Divide the numbers
t^{2}=\frac{1}{26}
Take the root of both sides of the equation and remember to use both positive and negative roots
t=\pm \sqrt{\frac{1}{26}}
Simplify the expression
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Evaluate
\sqrt{\frac{1}{26}}
To take a root of a fraction,take the root of the numerator and denominator separately
\frac{\sqrt{1}}{\sqrt{26}}
Simplify the radical expression
\frac{1}{\sqrt{26}}
Multiply by the Conjugate
\frac{\sqrt{26}}{\sqrt{26}\times \sqrt{26}}
When a square root of an expression is multiplied by itself,the result is that expression
\frac{\sqrt{26}}{26}
t=\pm \frac{\sqrt{26}}{26}
\text{Separate the equation into }2\text{ possible cases}
\begin{align}&t=\frac{\sqrt{26}}{26}\\&t=-\frac{\sqrt{26}}{26}\end{align}
Solution
t_{1}=-\frac{\sqrt{26}}{26},t_{2}=\frac{\sqrt{26}}{26}
Alternative Form
t_{1}\approx -0.196116,t_{2}\approx 0.196116
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