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Question
\frac{\sin\left(-x\right)}{\cos\left(-x\right)}
Simplify the expression
-\tan\left(x\right)
Evaluate
\frac{\sin\left(-x\right)}{\cos\left(-x\right)}
\text{Use }\sin(-t)=-\sin(t)\text{ to transform the expression}
\frac{-\sin\left(x\right)}{\cos\left(-x\right)}
\text{Use }\cos(-t)=\cos(t)\text{ to transform the expression}
\frac{-\sin\left(x\right)}{\cos\left(x\right)}
\text{Use }\frac{-a}{b}=\frac{a}{-b}=-\frac{a}{b}\text{ to rewrite the fraction}
-\frac{\sin\left(x\right)}{\cos\left(x\right)}
Solution
-\tan\left(x\right)
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