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\cos(2x)+2\sin^2(x)>0
Question
\cos\left(2x\right)+2\sin^{2}\left(x\right)>0
Uh oh!
Solve the inequality
x \in \mathbb{R}
Alternative Form
\textrm{All real solution}
Evaluate
\cos\left(2x\right)+2\sin^{2}\left(x\right)>0
Simplify
More Steps Hide Steps
Evaluate
\cos\left(2x\right)+2\sin^{2}\left(x\right)
Rearrange the terms
\cos^{2}\left(x\right)-\sin^{2}\left(x\right)+2\sin^{2}\left(x\right)
Rearrange the terms
\cos^{2}\left(x\right)+\sin^{2}\left(x\right)
Rewrite the expression
1
1>0
Solution
x \in \mathbb{R}
Alternative Form
\textrm{All real solution}

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