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Trigonometry
Question

frigonometric Substitution In Exercises \(57\) and...

frigonometric Substitution In Exercises \(57\) and 

\(58\) , use the trigonometric substitution to write the algebraic equation as a trigonometric equation of \(\theta\) , where \(- \pi / 2 < \theta < \pi / 2\) . Then find \(\sin \theta\) and \(\cos \theta\) . 57. \(\sqrt { 2 } = \sqrt { 4 - x ^ { 2 } } , x = 2 \sin \theta\) 

Answer

57 ) \(cos\theta= \frac{1}{\sqrt[4]{8} }\)

Solution
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