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Trigonometry
Question

Given: $$\overline { A P } \cong \overline { D P } ,$$ $$P$$ is the midpoint of $$\overline { C B }$$

Prove: $$\overline { A B } \cong \overline { D C }$$

$$\angle APB= \angle DPC$$
$$\triangle ABP\cong \triangle DCP$$
$$AB= DC$$