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Trigonometry
Question

Given: \( \overline { A P } \cong \overline { D P ...

Given: \( \overline { A P } \cong \overline { D P } , \) \( P \) is the midpoint of \( \overline { C B }\) 

Prove: \( \overline { A B } \cong \overline { D C }\) 

Answer

AP=DP

BP=CP

\(\angle APB= \angle DPC\)

\(\triangle ABP\cong \triangle DCP\)

\(AB= DC\)

Solution
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