Given: \( \overline { A P } \cong \overline { D P ...

Question

$Given: \( \overline { A P } \cong \overline { D P ...$

Given: $ \overline { A P } \cong \overline { D P } , $ $ P $ is the midpoint of $ \overline { C B }$

Prove: $ \overline { A B } \cong \overline { D C }$

Answer

AP=DP

BP=CP

$\angle APB= \angle DPC$

$\triangle ABP\cong \triangle DCP$

$AB= DC$

Solution

View full explanation on CameraMath App.