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Trigonometry
Question

Find the exact values of the six trigonometric ratios of the angle $$\theta$$ in the triangle. $$\sin ( \theta ) =$$

$$\cos ( \theta ) =$$

$$\tan ( \theta ) =$$

$$\csc ( \theta ) =$$

$$\sec ( \theta ) =$$

$$sin(\theta)= \frac{5}{\sqrt{89}}\\cos(\theta)= \frac{8}{\sqrt{89}}\\tan(\theta)= \frac{5}{8}\\csc(\theta)= \frac{\sqrt{89}}{5}\\sec(\theta)= \frac{\sqrt{89}}{8}\\cos(\theta)= \frac{8}{5}$$

Solution
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