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Trigonometry
Question

Assume that a spring does not follow Hooke's Law....

Assume that a spring does not follow Hooke's Law. Instead, the force required to stretch the spring \(x ft\) from its natural length is \(F ( x ) = 10 x ^ { 3 / 2 } lb\) . How much work does it take to

a. stretch the spring \(4 ft\) from its natural length?

b. stretch the spring from an initial \(1 ft\) past its natural length to \(5 ft\) past its natural length?

Answer

\(\text { (a) } 128 ft - lb \quad \text { (b) } 219.6 ft - lb\)

Solution
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