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Trigonometry
Question

A triangular field has sides of \( 218.5 m \) and ...

A triangular field has sides of \( 218.5 m \) and \( 213.3 m \) , and the angle between them measures \( 58.96 ^ { \circ } \) . Find the area of the field.

A. \( 14,332 m ^ { 2 } \) 

B. \( 12,016 m ^ { 2 } \) 

C. \( 24,032 m ^ { 2 } \) 

Answer

Area of triangle with SAS with is 

\(A = 0.5\times side_ 1\times side_ 2\times \sin \theta \\ \theta is angle between them\)

\(Area = 0.5\times 218.5\times 213.3\times \sin { 58.96} = 19,966.207232 m^ 2\)

Solution
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