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Trigonometry
Question

A mine shaft \( 100 m \) long is dug at an angle o...

A mine shaft \( 100 m \) long is dug at an angle of \( 20 ^ { \circ } 32 ^ { \prime } \) to the vertical. In metres, how far down will the end of the shaft be? 

Answer

100×cos(20\(° \)32')=93.6 m

Solution
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