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Trigonometry
Question

A \( 10 \) foot ladder is leaning against a buildi...

\( 10 \) foot ladder is leaning against a building. The ladder makes a \( 45 \) degree angle with the building. How far up the building does the ladder reach? 

A. \( 5 \sqrt { 2 } \) feet 

B. \( 20 \sqrt { 2 } \) feet 

C. \( 10 \sqrt { 2 } \) feet 

D. \( 5 \) feet 

Answer

10×sin45\(° \)=\(5\sqrt{2}\) feet

Solution
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