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Use linear approximation, i.e. the tangent line, to approximate $$\sqrt { 25.1 }$$ as follows: Let  f ( x ) =$$\sqrt { x }$$ . Find the equation of the tangent line to $$f ( x )$$ at $$x = 25$$   $$L ( x ) =$$
Using this, we find our approximation for $$\sqrt { 25.1 }$$ is
$$\sqrt{25.1}= 5.00999002$$