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Algebra
Question

Use linear approximation, i.e. the tangent line, t...

Use linear approximation, i.e. the tangent line, to approximate \( \sqrt { 25.1 } \) as follows: Let  f ( x ) =\(\sqrt { x } \) . Find the equation of the tangent line to \( f ( x ) \) at \( x = 25 \)   \( L ( x ) = \) 

 Using this, we find our approximation for \(\sqrt { 25.1 }\) is 

Answer

\(\sqrt{25.1}= 5.00999002\)

Solution
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