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Algebra
Question

Since YouTube first became available to the public...Since YouTube first became available to the public in mid-2005, the rate at which video has been uploaded to the site can be approximated by  \(v ( t ) = 1.1 t ^ { 2 } - 2.6 t + 2.3\) million hours of video per year \(( 0 \leq t \leq 9 )\) , where \(t\) is time in years since the start of June \(2005\) . \(t\) 

(a) Find an expression for the total number of hours \(V ( t )\) of video at time \(t\) (starting from zero hours of video at \(t = 0\) ). (Round your coefficients to four decimal place 

\(V ( t ) = \) 

Answer

a) V(t)=\(0.3667t^3- 1.3t^2+ 2.3t\)

b) 17 million

Solution
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