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Algebra
Question

Let \( f ( x ) = ( x - 8 ) ^ { 2 } \)Find a domain...

Let \( f ( x ) = ( x - 8 ) ^ { 2 } \)

Find a domain on which \( f \) is one-to-one and non-decreasing.

Find the inverse of \( f \) restricted to this domain. 

\(f ^ { - 1 } ( x ) = \) \( \square \) 

Answer

Domain = { x|x\(\in ( 8,+ \infty ) \)

\(f^ { - 1} ( x) = \sqrt { y} + 8 \)

 

Solution
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