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$$v ( t ) = 6 \sin ( 100 \pi t ) V$$ and $$i ( t ) = 10 \sin ( 100 \pi t ) + 9 \cos ( 100 \pi t ) A$$ . Then the average power delivered to the device over a $$20$$ ms interval (i.e. one period of the current and voltage waveform) (computed to one decimal place) is given by
$$\frac{2\pi}{100\pi}s= 0.02s= 20ms$$