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Given $$f ( x ) = \frac { 1 } { x + 1 }$$ and $$g ( x ) = \frac { 1 } { x - 3 } ,$$ find the domain of $$f ( g ( x ) )$$
f(g(x) = $$\frac{x- 3}{x- 2}$$  , domain = (-∞ , 2) U (2 , ∞)