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Algebra
Question

Find all the solutions to \(2{{\bf{e}}^{3\space y + 8}} - 11{{\bf{e}}^{5 - 10\space y}} = 0\). If there are no solutions clearly explain why.

Answer
\[\begin{align*}\ln \left( {{{\bf{e}}^{13\space y + 3}}} \right) & = \ln \left( {\frac{{11}}{2}} \right)\\ 13y + 3 & = \ln \left( {\frac{{11}}{2}} \right)\\ y & = {{\frac{1}{{13}}\left( {\ln \left( {\frac{{11}}{2}} \right) - 3} \right) = - 0.09963}}\end{align*}\]

 

Solution
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