Still have math questions?

Ask our expert tutors
Algebra
Question

An object is thrown upward at a speed of \( 176 \)...

An object is thrown upward at a speed of \( 176 \) feet per second by a machine from a height of \( 9 \) feet off the ground. The height \( h \) of the object after \( t \) seconds can be found using the equation \( h = - 16 t ^ { 2 } + 176 t + 9 \) When will the height be \( 82 \) feet? When will the object reach the ground? 

Answer

\(\frac{22±\sqrt{411} }{4}\)

\(\frac{22+ \sqrt{493} }{4}\)

Solution
View full explanation on CameraMath App.