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Algebra
Question

A theater group made appearances in two cities. Th...

A theater group made appearances in two cities. The hotel charge before tax in the second city was \( \$ 1500 \) higher than in the first. The tax in the first city was \( 6.5 \% \) , and the tax in the second city was \( 9.5 \% \) . The total hotel tax paid for the two cities was \( \$ 1022.50 \) . How much was the hotel charge in each city before tax? 

First city: \( \$ \square\) 

Second city: \( \$ \square\) 

Answer

let the hotel charge in first city before tax be x

hotel charge in second city before tax = x+1500 

tax paid in first city = 6.5%of x

tax paid in second city = 9.5% of  (x+15)

total tax = 1022.50

\(\frac{6.5}{100}x+ \frac{9.5}{100}(x+ 1500)\) = 1022.5

x= 6381.72

so

 hotel charge in first city before tax =$ 6381.72

 hotel charge in second city before tax = $ 7881.72

Solution
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