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Algebra
Question

A printer can complete a large job in $$8 hr$$ using a new machine. Using an older machine requires $$24 hr$$ to do the same job. How long would it take to complete the job using both machines?

$$\frac 18 t+ \frac 1{24}t= 1\\\frac t6= 1\\t= 6hr$$

Solution
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