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Algebra
Question

A motorboat travels \( 130 \) Kilometers in \( 5 \...

A motorboat travels \( 130 \) Kilometers in \( 5 \) hours going upstream. It travels \( 200 \) kilometers going downstream in the same amount of time. what is the rate of the boat in still water and what is the rate of the current. 

Answer

A motorboat travels 130 km in 5 hours going upstream. Rate = distance/time = 130/5 = 26 km/hr ---------------------- It travels 200 km going downstream in the same amount of time. Rate = distance/time = 200/4 =50 km/hr --------- What is the rate of the boat in still water and what is the rate of the current? Equations: Upstream: b-c = 26 km/hr Downstrm: b+c = 50 km/hr -------------------------------- Add and solve for "b": 2b = 76 km/hr b = 38 km/hr (speed of the boat in still water) ----- Solve for "c": b+c = 50 38 + c = 50 c = 12 km/hr (speed of the current)

Solution
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