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Algebra
Question

A ball is thrown upward from a height of \( 640 \)...

A ball is thrown upward from a height of \( 640 \) feet above the ground, with an initial velocity of \( 96 \) feet per second. From physics it is known that the velocity at time t is \(v ( t ) = 96 - 32 t\) feet per second. 

a) Find \( s ( t ) \) , the function giving the height of the ball at time t. 

b) How long will the ball take to reach the ground? 

c) How high will the ball go? 

Answer

a   s(t)=t(96-32t)

b   

c

Solution
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