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Algebra
Pregunta

A person throws a stone into the air. The height, ...

A person throws a stone into the air. The height, in feet, \( h ( t ) \) after \( t \) seconds is given by the following equation. 

\( h ( t ) = - 16 t ^ { 2 } + 66 t + 17 \) 

a. What is the height of the stone after \( 4 \) seconds? 

b. When is the stone at a height of \( 46 \) feet? 

c. When does the stone reach the ground? 

Answer

a.25

b.t=0.5s or t=3.625s

c. t=4.37s

Solución
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