¿Todavía tienes preguntas de matemáticas?

Pregunte a nuestros tutores expertos
Algebra
Pregunta

A particle is moving along a line in such a way th...

A particle is moving along a line in such a way that if \( v ( t ) \) is the velocity in \( cm / s \) of the particle at \( t \) seconds, then \( v ( t ) = 3 t ^ { 2 } + 2 t - 6 \) where the positive direction is to the right of the origin. If the particle is at the origin at the start of the motion, find its position when \( t \) is \( 4.8 \) seconds. 

Answer

\(3 \cdot 4.8 ^ { 2 } + 2 \cdot 4.8 - 6 = 72.72 \) 

Steps 

\( 3 \cdot 4.8 ^ { 2 } + 2 \cdot 4.8 - 6 \) 

Multiply the numbers: \( 2 \cdot 4.8 = 9.6 \) 

\( = 3 \cdot 4.8 ^ { 2 } + 9.6 - 6 \) 

Add \( / \) Subtract the numbers: \( 9.6 - 6 = 3.6 \) 

\( = 3 \cdot 4.8 ^ { 2 } + 3.6 \) 

\( 3 \cdot 4.8 ^ { 2 } = 69.12 \) 

\( = 69.12 + 3.6 \) 

Add the numbers: \( 69.12 + 3.6 = 72.72 \) 

\( = 72.72\) 

Solución
View full explanation on CameraMath App.