A company's revenue comes in at a rate of \( R ( t ) = 10000 e ^ { 0.07 t } \) from the beginning of \( 2008 \) to the beginning \( 2019 \) where \( t = 0\) corresponds with \( 2008 \) . Find the total value at the beginning of \( 2013 \) .
\(\$ 15,709.20 \)
\( \$ 59,866.79 \)
\( \$ 165,680.89 \)
\( \$ 78,546.37\)