A cable TV receiving dish is in the shape of a paraboloid of revolution. Find the location of the receiver, which is placed at the focus, if the dish is \( 6 \) feet across at its opening and \( 2 \) feet deep.

Pregunta

Answer

**I don't have the means to draw a sketch, but I can describe the parabola for you:** **Draw a parabola which opens upwards with the vertex at (0,0), one end at (-3,2) and the other at (3,2).** **Equation of the parabola: x^2=4py** **Location of the receiver will be p-ft from the vertex on the axis of symmetry, x=0.** **Using one of the points (3,2) to solve for p.** **3^2=4p*2** **9=8p** **p=9/8 ft**

**ans:** **The receiver will be placed at 9/8 ft above the vertex on the axis of symmetry.**