A cable TV receiving dish is in the shape of a paraboloid of revolution. Find the location of the receiver, which is placed at the focus, if the dish is \( 6 \) feet across at its opening and \( 2 \) feet deep.
I don't have the means to draw a sketch, but I can describe the parabola for you: Draw a parabola which opens upwards with the vertex at (0,0), one end at (-3,2) and the other at (3,2). Equation of the parabola: x^2=4py Location of the receiver will be p-ft from the vertex on the axis of symmetry, x=0. Using one of the points (3,2) to solve for p. 3^2=4p*2 9=8p p=9/8 ft
ans: The receiver will be placed at 9/8 ft above the vertex on the axis of symmetry.