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Algebra
Pregunta

A ball is launched vertically upward from a height...

A ball is launched vertically upward from a height of \( 200 ft \) above the ground, with an initial velocity of \( 1175 ft / sec \) . C. The path of the ball can be modeled using \(h ( t ) = - 16 t ^ { 2 } + v _ { 0 } t + h _ { 0 } \) , where \( h ( t ) \) is the ending height, \( v _ { 0 } \) is the initial velocity, and \( h _ { 0 } \) is the initial height. Step \( 2 \) of \( 4 : \) What is the height of the ball after \( 30 \) seconds? Round to the nearest tenth of a foot as needed. 

Answer

21050ft

Solución
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