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Algebra
Pregunta

4. The aspect ratio, or ratio of length to width o...

4. The aspect ratio, or ratio of length to width of the viewing area, of a wide-screen \( 42 \) -inch television is \( 16 : 9 \) . What are the dimensions of the rectangular viewing area to the nearest tenth? 

Answer

\(16: 9: \sqrt{337}= l: w: 42\\\Rightarrow l= 36.6,w= 20.6\)

Solución
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