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Algebra
Pregunta

1. The sum of six angles in an octagon (an eight s...

1. The sum of six angles in an octagon (an eight sided polygon) is \( 810 ^ { \circ } \) , and the other two angles are \( ( x + 50 ) ^ { \circ } \) and \( ( x - 34 ) ^ { \circ } \) . Find \( x \) . 2. Two angles of a triangle measure \( 30 ^ { \circ } \) and \( 58 ^ { \circ } \) . Find the measure of the third angle. 3. Find the sum of the measures of the interior angles of a 17-gon. equals \( 2880 ^ { \circ } \) ? 4. How many sides would a polygon have if the sum of all the interior angles equals \(2880 ^ { \circ }\) ? 

Answer

1)\(810° + (x+ 50)° + (x- 34)° = 1080° \)

\(x= 127° \)

2)third angle = \(180° - 30° - 58° = 92° \)

3)sum = \((17- 2)180° = 2700° \)

4)\(2880° = (n- 2)180° \)

n=18 sides

Solución
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