1. Let a function \( g \) be defined by
\(g ( x ) = \left\{ \begin{array} { c l } { x - 2 \sin ( x ) } & { , x \leq 0 } \\ { 1 } & { , x > 0 } \end{array} \right.\)
a) Determine whether \( g \) is continuous at \( x = 0 \) . Justify your answer.
b) For \( x \leq 0 , \) approximate the root of \( g \) using the Newton's method (in three decimal digits) with \( x _ { 0 } = - 2 \) .
a). \(g(x- 0)= 0\)
\(g(x+ 0)= 1\)
It is not continuous at x=0.
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
\( 8,40,200 , \ldots \)
Find the \( 10 \) th term.
(1) q) Put \( S \) above any dash that represents subtraction, \( N \) above any dash that represents negative and \( O \) above any dash that represents opposite. NOTE: You only need to give one answer if more than one answer is possible for a dash.
\( - ( 2 - ( - 3 ) ) - ( - 4 + ( - 2 ) ) + 4 ( - 5 ) + ( - ( - 3 ) )\)
